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In any circular motion, if the ratio between 2 fellow is n:1 then for each lap of the slower fellow, faster fellow overlaps him n times, except for the last lap of the slower fellow, where the number of crossings are n-1. (The race just finishes before the n th cross.
ReplyDeleteslower fellow : hour hand (short)
faster fellow : minuite hand (long)
n = 12
Total laps for hour hand = 2
total overlaps = 12+11 = 23.
it's 22. Don't listen to the haters
ReplyDelete